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Categories | Three Phase Voltage Monitoring Relay |
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Brand Name: | GINRI |
Model Number: | JVRD-380W |
Certification: | CE,CCC |
Place of Origin: | CHINA |
MOQ: | 20Pcs |
Payment Terms: | L/C, T/T, Western Union,Paypal |
Supply Ability: | 20000Pcs per month |
Delivery Time: | 1-30 days upon order quatity |
Packaging Details: | Voltage relay is standard seaworthy package,1pcs individual box or 5pcs in a middle box, 200pcs per carton. Base quotation is blank package. OEM design is acceptable. |
Function: | phase loss, over voltage, under voltage, phase unbalance |
Features: | Adjustable voltage |
Rated Voltage: | AC220V 380V 440V 460V 480V |
Output contacts: | 2C/O |
Contact Capacity: | 6A 250VAC |
Mounting: | Din Rail |
Air conditions part Three Phase Voltage Monitoring Relay under / over voltage adjustable
Due to short-circuit faults and other reasons, the line voltage will greatly reduce or even disappear within a short time. It will cause damage to lines and electrical equipment. For example, if the motor is worn down or blocked, an overcurrent of several times the rated current will be generated and the motor will be burned out. When the voltage recovers, the self-start of a large number of motors will cause the voltage of the motor to drop drastically and cause damage.
The voltage that causes the motor to wear out is called the
critical voltage. When the line voltage is reduced to the critical
voltage, the action of protecting the electrical equipment is
called undervoltage protection. Its task is mainly to prevent the
equipment from being burned due to overload. When the voltage of
the circuit is lower than the threshold voltage, the protective
device is called the loss of voltage protection. Its main task is
to prevent the motor from starting.
Taking the power equipment on the line as an example, if the power cannot keep up, the voltage will decrease very much. According to the formula: P=U*I, U becomes smaller, I becomes larger, and U is smaller. The bigger will be.
For example, if U is U1 at the beginning, I=I1=P/U1 at this time.
If the energy cannot keep up at this time, because the power P
required by the power-consuming equipment is certain, then U will
drop to 0.5U1. Current:
I=P/U=P/(0.5U1)=2*(P/U1)=2I1
In other words, if the voltage drops to half, then the current will
be twice as high.
The problem arises in this case, according to the well-known
Joule's law: heat Q=I*R*T
Any device on the line resistance R is certain, if, before the
circuit heat is Q1 = I1*R*T, after the voltage U changes to 0.5U1,
the current I is 2I1, at this time the line heat Q2 = I*R* T =
(2I1) * R * T = 4 * I1 * R * T = 4Q1, that is, if the voltage is
reduced by half, then the amount of heat generated by the line per
unit time becomes four times.
It can be seen that the change of the heat generation per unit time
of the device on the line is inversely proportional to the square
of the change of the line voltage, so the more severe the voltage
drop, the greater the heat generation of the device on the line. If
the device heat accumulation on the line exceeds the thermal
diffusion The speed of the device will become higher and higher,
and it may cause accidents such as fire.
Therefore, it is necessary to set a critical voltage for the line.
When the line voltage drops to this critical voltage, the line is
cut off through a relay protection device or a device with similar
function, thereby ensuring that the device devices on the entire
circuit will not be burned out. This is called undervoltage
protection.
♦ Technical data
Type | JVRD-W |
Measuring circuit | L1,L2,L3 |
Rated voltage | 220VAC,380VAC,440VAC, 460VAC,480VAC,50/60Hz |
Monitoring functions | phase sequence,phase loss,overvoltage, undervoltage,phase unbalance |
Voltgae setting range | ±5%~±20% adjustable |
Indicators | phase sequence,phase loss,overvoltage, undervoltage and normal |
Output contacts | 2 C/O |
Contact capacity | 6A,250VAC |
Dimensions(H*W*D) | 79*23*79mm |
Mounting | DIN Rail |
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